Empirical formula the simplest ratio of an element in molecular formula
(Empirical formula)n = Molecular compound
Example of RELATIONSHIP:
| COMPOUND | MOLECULAR FORMULA | EMPIRICAL FORMULA | VALUE OF n |
| Glucose | C6H12O6 | CH2O | 6 |
| Carbon dioxide | CO2 | CO2 | 1 |
| Water | H2O | H2O | 1 |
| Benzene | C6H6 | CH | 6 |
| Hydrogen Peroxide | H2O2 | HO | 2 |
| Butene | C4H8 | CH2 | 2 |
| Butane | C4H10 | C2H5 | 2 |
| Ethane | C2H6 | CH3 | 2 |
Example Questions :
(a) What empirical formula of hexane, C6H14?
Solution :
Step 1:
Find simplest ratio between carbon and hydrogen in compound.
[ Use fractional of each element]
= C6/2 H14/2
Step 2:
Divisible is value of n; n=2 ⇒ (empirical formula) n = molecular formula
= (C3H7)2
Step 3:
Empirical formula
= C3H7
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